Two brokers split a 6% commission equally on a $146,000 home. The selling salesperson, Joe, was paid 70 percent of his broker's share. The listing salesperson, Janice, was paid 30 percent of her broker's share. How much did Janice receive?

Two brokers split a 6% commission equally on a $146,000 home. The selling salesperson, Joe, was paid 70 percent of his broker's share. The listing salesperson, Janice, was paid 30 percent of her broker's share. How much did Janice receive?

• A. 1,314
• B. 3,066
• C. 1,500
• D. 2,000

Answer: (A)

The key idea is how a sale’s total commission is divided and then distributed to each agent. First, the total commission on a $146,000 home at 6% is 0.06 × 146,000 = 8,760. This is split equally between the two brokers, so each broker gets 8,760 ÷ 2 = 4,380. Each broker then allocates their own share to the agents: the selling agent receives 70% of their broker’s share, and the listing agent receives 30% of theirs. For the listing side, Janice’s broker share is 4,380, and 30% of that is 0.30 × 4,380 = 1,314. Therefore, Janice receives 1,314. (For context, the selling agent would receive 0.70 × 4,380 = 3,066, and the two sums equal their broker’s 4,380.)

The key idea is how a sale’s total commission is divided and then distributed to each agent. First, the total commission on a $146,000 home at 6% is 0.06 × 146,000 = 8,760. This is split equally between the two brokers, so each broker gets 8,760 ÷ 2 = 4,380. Each broker then allocates their own share to the agents: the selling agent receives 70% of their broker’s share, and the listing agent receives 30% of theirs. For the listing side, Janice’s broker share is 4,380, and 30% of that is 0.30 × 4,380 = 1,314. Therefore, Janice receives 1,314. (For context, the selling agent would receive 0.70 × 4,380 = 3,066, and the two sums equal their broker’s 4,380.)