A lot has a frontage of 75 feet 6 inches and a depth of 140 feet 9 inches. What is the approximate total square feet of the lot?

A lot has a frontage of 75 feet 6 inches and a depth of 140 feet 9 inches. What is the approximate total square feet of the lot?

• A. 10,626.63
• B. 11,000
• C. 9,900
• D. 10,000

Answer: (A)

When a lot is described by frontage and depth, treated as a rectangle, its area is found by length times width. Convert the measurements to feet: 75 ft 6 in is 75.5 ft, and 140 ft 9 in is 140.75 ft. Multiply 75.5 by 140.75 to get 10,626.625 square feet. Rounding gives about 10,626.63 square feet, which matches the given option.

When a lot is described by frontage and depth, treated as a rectangle, its area is found by length times width. Convert the measurements to feet: 75 ft 6 in is 75.5 ft, and 140 ft 9 in is 140.75 ft. Multiply 75.5 by 140.75 to get 10,626.625 square feet. Rounding gives about 10,626.63 square feet, which matches the given option.